Question 1

Differentiate

Expected answer:

This feedback is based on your last submitted answer. Submit your changed answer to get updated feedback.

Score: 0/1

Unanswered

Or, you could:

There's nothing more to do from here.

If $y = \mathrm{f}(x) + \mathrm{g}(x)$ then $\frac{dy}{dx}=\frac{d}{dx}\mathrm{f}(x)+\frac{d}{dx}\mathrm{g}(x)$.

In this case

$\mathrm{f}(x) = \simplify{{a}x^{n_1}}$, so $\frac{d}{dx}\mathrm{f}(x) = \simplify{{a}*{n_1}x^{n_1-1}}$
$\mathrm{g}(x) = \simplify{{b}x^{n_2}}$, so $\frac{d}{dx}\mathrm{g}(x) = \simplify{{b}*{n_2}x^{n_2-1}}$

$\frac{dy}{dx}= \simplify[all,!noLeadingMinus]{{a}*{n_1}x^{n_1-1} + {b}*{n_2}x^{n_2-1}}$

Total	0/1

Numbas has failed