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Complete the square on x2−2x
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You are asked to complete the square on $\simplify{x^2+{b}x}$
The exponent of x is -2, so we halve it to get $\var{p}$.
Squaring this gives $\var{p^2}$.
We can write
\[\simplify{x^2+{b}x} = \simplify{x^2+{b}x} + \var{p^2} - \var{p^2}\]
The first three terms are a perfect square, so we have
\[\simplify{x^2+{b}x} = \simplify{(x+{p})^2} - \var{p^2}\]
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