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y=−2x−2
y=4x2−x−3
Substituting the linear equation into the quadratic, and solving, what are the values of x?
x1=Round your answer to 3 significant figures.question.score feedback.none Expected answer:
x2=Round your answer to 3 significant figures.question.score feedback.none Expected answer:
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What are the y values?
Round your answer to 3 significant figures.question.score feedback.none Expected answer: and Round your answer to 3 significant figures.question.score feedback.none Expected answer:
You are given that
Substituting the first equation into the second gives
−2x−2=4x2−x−3
Which rearranges to give
4x2+x−1=0
Which can be solved to give x=−0.64 and x=0.39.
Hence y=−0.719 and y=−2.78
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